Why pass by reference supporting languages will always be superior...

Because in pass by reference (pointer) supporting languages like C, for one thing, you can switch the values of two variables, a and b without needing a temp variable, which you cannot in a language without pointers, or, at least far less straight forwardly as far as I can see. See code below. :-)

Signed,

An unrepentant acolyte of Bell Labs' Kernighan and Ritchie's C programming language.

#include <stdlib.h>
#include <stdio.h>

int main(int argc, char *argv[])
{
char *a = (char*)malloc(sizeof(char)*8); //initializing string a
strcpy(a,"A string");

char *b = (char*)malloc(sizeof(char)*8); //initializing string b
strcpy(b,"B string");

printf("a is %s\n",a);
printf("b is %s\n",b);

printf("\nswitching values...\n\n");

////////////
//a = a + b;
////////////
if ( ( a = realloc(a, sizeof(char)*2*strlen(a) ) ) == NULL ) //Note: realloc only works for strings made with malloc in the first place
{
printf("Error reallocating memory to string a. System terminating with return value 1.\n");
return 1;
}

char *aPtr = &a[strlen(b)];
char *bPtr = &b[0];
while(*bPtr != '\0') *aPtr++ = *bPtr++;

////////////
//b = a - b;
////////////
aPtr = &a[0];
bPtr = &b[0];
while(*aPtr != a[strlen(b)]) *bPtr++ = *aPtr++;

////////////
//a = a - b;
////////////
int i = 0;
for( ; i < strlen(b); ++i) { a[i] = a[i + strlen(b)]; }
for( i = strlen(b); i < strlen(a); ++i) { a[i] = '\0'; }

printf("a is now %s\n",a);
printf("b is now %s\n",b);

free(a);
free(b);
free(aPtr);
free(bPtr);

printf("\nPress any key to continue...\n");
getc(stdin);
return 0;
}

Output of the above code looks like this on the console:

C:\Dev-Cpp\VariableTest>VariableTest.exe
a is A string
b is B string

switching values...

a is now B string
b is now A string

Press any key to continue...